How to change a variable after each nested case?

[ymic9963]

Contributing guidelines

• I have read CODE_OF_CONDUCT.md

Module(s)

mini.test

Question

This is a bit of a strange one to describe but I'll do my best. Essentially I have two functions using different implementations (one is using treesitter the other is using patterns) but they are returning the exact same thing. Currently I have the tests like this,

local expected = ... -- whatever
local ret = child.lua([[ return func_re() ]])
eq(ret, expected)
ret = child.lua([[ return func_ts() ]])
eq(ret, expected)

Ideally I would like to be able to do this,

local expected = ... -- whatever
local ret = func()
eq(ret, expected)

where func() would change between child.lua([[ return func_re() ]]) and child.lua([[ return func_ts() ]]). Is this possible to do in any way? I thought about using nested tests, but you can't have something specific to change per test. Or at least I haven't understood the docs well enough to know how to do something like this.

[TanbirRamim]

parametrize does this. put the tests in a set parametrized by the function name and every case inside runs once per entry, getting it as an argument:

T['impl'] = MiniTest.new_set({ parametrize = { { 'func_re' }, { 'func_ts' } } })

T['impl']['returns the thing'] = function(fname)
  local ret = child.lua('return ' .. fname .. '()')
  eq(ret, expected)
end

works for nested sets too, everything under T['impl'] gets multiplied. there's a small example under :h MiniTest.new_set().

[ymic9963]

Oh wow I didn't think to parametrize the strings! Thanks!